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If the Silva family has 6 children and the Oliveira family has 4, what is the probability that all the Silva children will be girls and all the Oliveira children will be boys?

a) 1/512
b) 1/682
c) 1/921
d) 1/1754
e) 1/1024​


Sagot :

✒️[tex]\large{\mathcal{ANSWER}}[/tex]

[tex]======================[/tex]

The probability that all Silva children are girls and all Oliveira children are boys is 1/1024,

Alternative E.

  • The chances of any couple having a boy or girl is a fil 50%, represented as a fraction is 1/2.

[tex]------------------[/tex]

The probability that all of the Silva family's children are girls is;

[tex]( \frac{1}{2} )^{6} = \frac{1}{64} [/tex]

The probability that all the children of the Oliveira family are boys is;

[tex]( \frac{1}{2} ) ^{4} = \frac{1}{16} [/tex]

Therefore, the probability that all children of the Silva family are girls and all children of the Oliveira family are boys is:

[tex] \frac{1}{64} \times \frac{1}{16} = \frac{1}{1024} [/tex]

Therefore, the correct alternative is letter E [tex]\frac{1}{1024} [/tex]

[tex]======================[/tex]

letter e ang tamang sagot,thank you