Eulamelieidn
Answered

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A. Mark's first 3 scores in his Math tests were 89, 84, and 87. What must be his score in his fourth test to have an average of at least 88?​

Sagot :

Ranzelario14idn

Answer:

X = 93

Step-by-step explanation:

You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.

Solving for the average is simple:

Add up all of the exam scores and divide that number by the number of exams you took.

(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.

Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:

(87 + 88 + 92 + X) / 4 = 90

Now you need to solve for X, the unknown:

87

+

88

+

92

+

X

4

(4) = 90 (4)

Multiplying for four on each side cancels out the fraction.

So now you have:

87 + 88 + 92 + X = 360

This can be simplified as:

267 + X = 360

Ayaario07idn

Answer:

85

Step-by-step explanation:

Scott took 7* math tests in one semester. His scores were 89 , 73 , 84 , 91 , 87 , 77 , 94.

Find the mean. To solve for the mean, add all the scores together, and divide by the amount of tests he took:

(89 + 73 + 84 + 91 + 87 + 77 + 94)/7

(595)/7 = 85

Scott's mean test score is 85.

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