Answer:
The given quadrilateral ∆BCD consists of two triangles; ∆ABD and ∆BCD
The area of quadrilateral ABCD = The sum of the areas of ∆ABD and ∆BCD
The base length of the two triangles equals segment BD 11 cm
The height of triangle ∆ABD = 7 cm
The area of a triangle = (1/2) * Base length x Height
The area of triangle ∆ABD = (1/2) x 11 cm x 7 cm = 38.5 cm²
Similarly;
The area of triangle ∆BCD (1/2) x 11 cm x 5 cm = 27.5 cm²
The area of quadrilateral ABCD = 38.5 cm + 27.5 cm² = 66 cm²
The area of the given figure (quadrilateral ABCD) = 66 cm²
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Step-by-step explanation:
V4x2 + x ? D. X B. V A 4x² + x C. 2 2. What is the radicand of the radical expression in problem number A 4x²+x B. 7 C. 2 D.X 3. If a > 0, then Va is the nath root of a D. index A. 72 B. positive c. negative
