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Anthony used 3/4 meter from a 9/10 meter of bamboo for his project. How long was the piece of bamboo left ?
1. What is asked in the problem?
A. The length of the bamboo left.
B. The total meter of bamboo.
C. The number of pieces of bamboo left.
D. The length of the bamboo used.

2. What is the mathematical sentence for the above problem?
A. 3/4 + 9/10 = N
B. 3/4 x 9/10 = N
C. 3/4 - 9/10 = N
D. 3/4 ÷ 9/10 = N

3. What is the answer to the above problem?
A. 7/10
B. 3/20
C. 5/40
D. 6/6​


Sagot :

✒️ ANSWER:

1. B. The total meter of bamboo.

2. C. 3/4 - 9/10

3. B. 3/20

STEP BY STEP EXPLAINATION:

3/4 - 9/10

Write all numerators above the least common denominator 20

DETAILED STEPS:

3/4 - 9/10

expand the fraction to get the least common denominator

[tex] \frac{3 \times 5}{4 \times 5} - \frac{9}{10} [/tex]

expand the fraction to get the least common denominator

[tex] \frac{3 \times 5}{4 \times 5} - \frac{9 \times 2}{10 \times 2} [/tex]

multiply the numbers

3×5

15

multiply the numbers

4×5

20

[tex] \frac{15}{20} - \frac{9}{10} [/tex]

multiply the numbers

9×2

18

multiply the numbers

10×2

20

[tex] \frac{15}{20} - \frac{18}{20} [/tex]

write all numerators above the least common denominator

[tex] \frac{15 - 18}{20} [/tex]

calculate the difference

[tex] \frac{ - 3}{20} [/tex]

DETAILED STEPS:

15 - 18

keep the sign of the number with the larger absolute value and subtract the smaller absolute value from the larger

- (18-15)

subtract the numbers

-3

[tex] \frac{ - 3}{20} [/tex]

use , to rewrite the fraction

[tex]\frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b} [/tex]

[tex] - \frac{3}{20} [/tex]

SULUTION:

[tex] \frac{3}{20} [/tex]

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