Suriin ang IDNStudy.com para sa mabilis at maaasahang mga solusyon. Ang aming komunidad ay handang magbigay ng malalim at maaasahang mga sagot, anuman ang kahirapan ng iyong mga katanungan.

the perimeter of a rectangle, whose length is five centimeters more than its width, is fifty centimeters

Sagot :

Let width be x
Length be x + 5 (five centimeters more than the width)
Perimeter = 50 cm.

Perimeter of rectangle = 2 (L) + 2(W)
50 = 2 (x + 5) + 2(x)
50 = 2x + 10 + 2x

50 = 4x + 10  (Subtract 10 from each side of equation)
50-10 = 4x 10-10
40 = 4x 
40/4 = 4x/4

x = 10 cm (width)

The dimensions are:
Width: x = 10 cm
Length = x + 5 = 10 + 5 = 15 cm

To check:

2(L) + 2(W) = 50 cm
2(15 cm) + 2(10 cm) = 50
30 cm + 20 cm = 50 cm
   50 cm = 50 cm