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Give the slope-intercept form and standard form of the following
1. m=-6, b=3
2. (2,-3), b=1
3. (2,-3) and (0,1)


Sagot :

Slope Y-intercept Form
1. y = -6x + 3
2. y = -2x + 1 
3. y = -2x + 1
Standard Form
1. 6x + y = 3
2. 2x + y = 1
3. 2x + y = 1

~hope it help :)

Slope Intercept Form ----- y = mx + b
Standard Form ----- ax + by = c

1. m = -6, b = 3
 
       SIF: y = mx + b
              y = -6x + 3 (just substitute)

       SF: y = -6x + 3
             transpose variables to the other side such that it'll have the format of sf
             
6x + y = 3

2. (2, -3) ; b = 1

       
SIF: y = mx + b                    
              -3 = 2m + 1
              -4 = 2m
             ----   -----
              2      2
              m = -2   ---- Now we have m then substitute so the answer is
                                y = -2x + 1.
 
       
SF: y = -2x + 1
             2x + y = 1

3. (2, -3) and (0, 1)


     SIF: (solve for m)
                   change in y
            
m = -----------------
                   change in x
 
                   1 + 3
                = --------
                   0 - 2
                      
                      4
                = ---------- or -2  so therefore, m = -2
                     - 2 
              
              y = mx + b
             1 = -2(0) + b                  SIF: y = -2x + 1
             1 = b
             b = 1
 
       SF: y = -2x + 1
             2x + y = 1     

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