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Learning Task 2 :Find the area of the

Standard region. Use = 3.14.




Learning Task 2 Find The Area Of The Standard Region Use 314 class=

Sagot :

Answer:

AREA OF CIRCLE

\mathbb{PROBLEM:}PROBLEM:

Learning Task 2: In your answer sheet, copy and find the area of the shaded region.

\mathbb{SOLUTION:}SOLUTION:

»Find The Diameter

\bold{diameter} = 2rdiameter=2r

d = 2 \times \green{9}d=2×9

\boxed{d = \green{18} }

d=18

»Find The Circumferance

\bold{circumferance} = 2\pi \orange{r}circumferance=2πr

c = 2 \times \pi \times \green{9}c=2×π×9

c = 18 \green{\pi}c=18π

c = 56. \green{54}c=56.54

»Find The Area

\bold{area} = \pi \orange{r}^{2}area=πr

2

a = \pi \times {9}^{2}a=π×9

2

a = 81\pia=81π

a = 254. \green{469005}a=254.469005

So the are is \boxed{a = 254. \green{469005} \: in \: ^{2} }

a=254.469005in

2

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diko lang po sure .. hehe