Queenylynhoraidn
Answered

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2. A hypothetical element consists of the following naturally occurring isotopes. What is the atomic weight of the element? (5 points) Isotopes Mass Abundance 1 46.041 amu 26.00 % 2 47.088 amu 58.00 % 3 49.034 amu 16.00 % 31​

Sagot :

Cheyenne6345idn

Answer:

47.13 amu

Explanation:

Atomic Weight = (Isotope 1 mass) (Isotope 1 abundance) + (Isotope 2 mass) (Isotope 2 abundance) + (Isotope 3 mass) (Isotope 3 abundance)

Isotope 1: (46.041amu)(26%) = 11.97066 amu

Isotope 2: (47.088amu)(58%) = 27.31104amu

Isotope 3: (49.034amu)(16%) = 7.84544amu

Sum of all Isotopes: 11.97066+27.31104+7.84544 = 47.12714amu