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what are the x-intercepts of the polynomial F (X)=X(x-2)(X+5)(X+4)?


Sagot :

[tex]\large{\mathcal{SOLUTION:}}[/tex]

To find the x-intercepts , equate the function to zero and solve for the values of x

  • f(x) = x(x-2)(x+5)(x+4)
  • 0 = x(x-2)(x+5)(x+4)

By zero product property

  • x = 0
  • x-2 = 0 , x = 2
  • x+5 = 0 , x = -5
  • x+4 = 0 , x = -4

Therefore , the x-intercepts are 0,2,-5, and -4

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[tex]\large{\mathcal{ANSWER:}}[/tex]

  • the x-intercepts are 0,2,-5, and -4

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[tex]\boxed{\begin{array}{} \blue{\text{DON'T RELY ON CHANCES,}} \\ \red{\text{ WORK FOR THE HARDEST }} \\ \end{array}}[/tex]