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Identify the equation of the quadratic function that passes through (0,2), (-2,1), and (2,5).​

Sagot :

Rennamaecoronel69idn

where a,b and c are all real numbers and a≠0 .

If we replace 0 with y , then we get a quadratic function

y=ax2+bx+c

whose graph will be a parabola .

The axis of symmetry of this parabola will be the line x=−b2a . The axis of symmetry passes through the vertex, and therefore the x -coordinate of the vertex is −b2a . Substitute x=−b2a in the equation to find the y -coordinate of the vertex. Substitute few more x -values in the equation to get the corresponding y -values and plot the points. Join them and extend the parabolic