Answer:
merry Christmas
》 two arithmetic means between 13 and -2 is 8 and 23.
\begin{gathered}an = a1 + (n - 1)d \\ - 2 = 13 + (4 - 1)d \\ - 2 - 13 = 3d \\ \frac{ - 15}{3} = \frac{3d}{3} \\ - 5 = d \end{gathered}an=a1+(n−1)d−2=13+(4−1)d−2−13=3d3−15=33d−5=d
\begin{gathered}an = a1 + (n - 1)d \\ a2 = 13 + (2 - 1) - 5 \\ a2 = 13 + (1) - 5 \\ a2 = 13 + (- 5) \\ a2 = 8\end{gathered}an=a1+(n−1)da2=13+(2−1)−5a2=13+(1)−5a2=13+(−5)a2=8
\begin{gathered}an = a1 + (n - 1)d \\ a3 = 13 + (3 - 1) - 5 \\ a3 = 13 +(2) - 5 \\ a3 = 13 +10 \\ a3 = 23\end{gathered}an=a1+(n−1)da3=13+(3−1)−5a3=13+(2)−5a3=13+10a3=23
\begin{gathered}an = a1 + (n - 1)d \\ a4 = 13 + (4 - 1) - 5 \\ a4 = 13 +(3) - 5 \\ a4 = 13 +( - 15) \\ a4 = - 2\end{gathered}an=a1+(n−1)da4=13+(4−1)−5a4=13+(3)−5a4=13+(−15)a4=−2
plss pa brinly
