Arianeramos3333idn
Answered

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Solve for the roots of the rational algebraic equation?
[tex] \frac{2}{x - 2} = \frac{4}{x + 1} + 1[/tex]
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Sagot :

AnonymousBetaidn

Step-by-step explanation:

2/(x-2) = 4/(x+1) + 1

2/(x-2) = ( 4 + x + 1) / (x + 1)

2/(x-2) = (x+5)/(x+1)

2/(x-2) - (x+5)/(x+1) = 0

[2(x+1) - (x+5)(x-2)] /[(x-2)(x+1)] = 0

(2x + 2 - x^2 -3x + 10 )/ [(x-2)(x+1)] =0

(-x^2 - x + 12)/ [(x-2)(x+1)]

-(x+4)(x-3) / [(x-2)(x+1)] = 0

Dont mind the denominator as you will get undefined/indeterminate answers so focus on the numerator

(x+4)(x-3) = 0

x= - 4

x = 3