7x²+3x=0, make a value 1 so dive all by 7
x²+3/7x=0,
x²+3/7x+3/196=3/196, complete the square of x
(x+3/14)²=3/196,express the term on the right as square of binomial
x+3/14=√3/√196, extract the square roots
x+3/14=+or-√3/14, only 196 ha square root so 3 remain the same
x=3/14+or-√3/14, apply ape
first solution is
x=3/14+√3/14
the second is
x=3/14-√3/14
the equation is unfactorable but this are the solutions
