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Sagot :
Five consecutive numbers:
Let first number: x
second number: x + 1
third number: x + 2
fourth number: x + 3
fifth number: x + 4
The sum of the numbers is 35.
(x) + (x+1) + (x+2) + (x + 3) + (x+4) = 35
5x + 10 = 35
5x = 35 - 10
5x = 25
5 5
x = 5
First Number: x = 5
Second number: x + 1
5 + 1 = 6
Third number: x + 2
5 + 2 = 7
Fourth number: x + 3
5 + 3 = 8
Fifth number: x + 4
5 + 4 = 9
The five numbers are: 5, 6, 7 ,8, 9
Their LCM, prime factorization:
5 = 5 × 1
6 = 2×3
7 = 7×1
8 = 2×2×2
9 = 3 × 3
Cancel the factors that appeared in other number, that it, the factors of second number 6 have appeared in factors of numbers 8 and 9
LCM : 5 × 7 × 2³ × 3² = 2,520.
LCM = 2,520
Let first number: x
second number: x + 1
third number: x + 2
fourth number: x + 3
fifth number: x + 4
The sum of the numbers is 35.
(x) + (x+1) + (x+2) + (x + 3) + (x+4) = 35
5x + 10 = 35
5x = 35 - 10
5x = 25
5 5
x = 5
First Number: x = 5
Second number: x + 1
5 + 1 = 6
Third number: x + 2
5 + 2 = 7
Fourth number: x + 3
5 + 3 = 8
Fifth number: x + 4
5 + 4 = 9
The five numbers are: 5, 6, 7 ,8, 9
Their LCM, prime factorization:
5 = 5 × 1
6 = 2×3
7 = 7×1
8 = 2×2×2
9 = 3 × 3
Cancel the factors that appeared in other number, that it, the factors of second number 6 have appeared in factors of numbers 8 and 9
LCM : 5 × 7 × 2³ × 3² = 2,520.
LCM = 2,520
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