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Sagot :
Find four consecutive even integers whose sum is 524.
Let first even integer: x
second even integer: x + 2
third consecutive even integer: X + 4
fourth consecutive even integer: x + 6
Sum= 524
Add:
(x) + (x+2) + (x+4) + (x+6) = 524
4x + 12 = 524
4x = 524 - 12
4x = 512
4x = 512
4 4
x = 128
The four consecutive integers are
first: x = 128
second : x + 2 = 128 + 2 = 130
third: x + 4 = 128 + 4 = 132
fourth: 128 + 6 = 134
FINAL ANSWER: The four consecutive even integers are 128, 130, 132 and 134
Let first even integer: x
second even integer: x + 2
third consecutive even integer: X + 4
fourth consecutive even integer: x + 6
Sum= 524
Add:
(x) + (x+2) + (x+4) + (x+6) = 524
4x + 12 = 524
4x = 524 - 12
4x = 512
4x = 512
4 4
x = 128
The four consecutive integers are
first: x = 128
second : x + 2 = 128 + 2 = 130
third: x + 4 = 128 + 4 = 132
fourth: 128 + 6 = 134
FINAL ANSWER: The four consecutive even integers are 128, 130, 132 and 134
Cody is twice as old as Evan. Three years ago, the sum of their ages was 27. Find the age of each boy now.
Representation: Let x = Evan's age
2x = Cody's age
Three years ago Now
Cody 2x - 3 2x
Evan x - 3 x
Equation: (2x - 3) + (x - 3) = 27
Solution: (2x - 3) + (x - 3) = 27
2x - 3 + x - 3 = 27
3x - 6 = 27
3x = 33
----- ----- ⇒ x = 11; 2x = 22
3 3
Answer: Cody is 22 while Evan is 11.
Check: (2x - 3) + (x - 3) = 27
[2(11) - 3] + (11 - 3) = 27
(22 - 3) + 8 = 27
19 + 8 = 27
27 = 27
--
---Have a vigorous Friday---
Representation: Let x = Evan's age
2x = Cody's age
Three years ago Now
Cody 2x - 3 2x
Evan x - 3 x
Equation: (2x - 3) + (x - 3) = 27
Solution: (2x - 3) + (x - 3) = 27
2x - 3 + x - 3 = 27
3x - 6 = 27
3x = 33
----- ----- ⇒ x = 11; 2x = 22
3 3
Answer: Cody is 22 while Evan is 11.
Check: (2x - 3) + (x - 3) = 27
[2(11) - 3] + (11 - 3) = 27
(22 - 3) + 8 = 27
19 + 8 = 27
27 = 27
--
---Have a vigorous Friday---
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