This is linear.
Let the first odd integer = x
second odd integer = X + 2
third odd integer = x+4
(x) (x + 2) = (x + 4)² - 58
x² + 2x = x² + 8x + 16 - 58
x² - x² + 2x - 8x - 16 + 58 = 0
-6x + 42 = 0 (linear equation)
-6x = -42
-6 -6
x = 7
Substitute 7 for x
First odd integer: x = 7
Second odd integer: x + 2
7 + 2
= 9
third odd integer: x + 4
7 + 4
= 11
The three consecutive odd integers are 7, 9, 11