Sumali sa IDNStudy.com at tuklasin ang komunidad ng pagbabahagi ng kaalaman. Anuman ang kahirapan ng iyong mga tanong, ang aming komunidad ay may mga sagot na kailangan mo.

The area of a 6 cm by 4 cm rectangle is to be doubled. by what equal length mus each dimension be increased?

PLEASE SHOW ME YOUR SOLUTION and btw our topic is about quadratic equations :)


Sagot :

Area of rectagnle = (L) (W)
Area = (6cm) (4 cm)
Area = 24 cm² 

If area is to be doubled, with equal length added to  each dimension:

Let x = length added to each dimension
      6 + x = length
      4 + x = width
      2 (24) = area doubled

Equation:
      2 (24) = (6 + x) (4 + x)
      48 = 24 + 6x + 4x + x²
 
Rewrite to standard form:
     x² + 10x + 24-48 = 0
    x² + 10x - 24 = 0

Factor:
   (x - 2) (x + 12) = 0
   x - 2 = 0                       x + 12 = 0
   x = 2                            x = -12
   
Choose the positive root for distance, that is,  x=2 
                                       
Therefore, each dimension must be increased by 2 cms. to double the area from the original area given :-)