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Sagot :
1. 5x - y = 7
x = 2
y = 3
5(2) - 3
10 - 3
= 7
2. -3x - 2y = 12
x = 2
y = 3
-3(2) - 2(3)
-6 - 6
= -12
x = 2
y = 3
5(2) - 3
10 - 3
= 7
2. -3x - 2y = 12
x = 2
y = 3
-3(2) - 2(3)
-6 - 6
= -12
Using substitution method to get the answer provided by Awesome Helper (and I hope that this solution stays here. Thank you.)
Equation 1) 5x - y = 7
Equation 2) - 3x - 2y = -12
Step 1, using Equation 1
5x - y = 7
-y = -5x + 7
y = 5x - 7
Equation 3: y = 5x - 7
Step 2: Using Equation 2, substitute 5x-7 for y
-3x - 2y = -12
-3x - 2 (5x - 7) = -12
- 3x - 10x + 14 = -12
-13x = -12 - 14
-13x = -26
-13 -13
x = 2
Step 3, Using Equation 3, substitute 2 for x
y = 5x - 7
y = 5 (2) - 7
y = 10 - 7
y = 3
The solution to this system is x = 2; y = 3
Equation 1) 5x - y = 7
Equation 2) - 3x - 2y = -12
Step 1, using Equation 1
5x - y = 7
-y = -5x + 7
y = 5x - 7
Equation 3: y = 5x - 7
Step 2: Using Equation 2, substitute 5x-7 for y
-3x - 2y = -12
-3x - 2 (5x - 7) = -12
- 3x - 10x + 14 = -12
-13x = -12 - 14
-13x = -26
-13 -13
x = 2
Step 3, Using Equation 3, substitute 2 for x
y = 5x - 7
y = 5 (2) - 7
y = 10 - 7
y = 3
The solution to this system is x = 2; y = 3
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