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Sagot :
Alden is three years older than Yaya
Dub. The product of their ages is
460. Determine their ages.
Let x age of Yaya Dub
x + 3 age of Alden
460 product of their ages
Equation:
(x) (x + 3) = 460
x² + 3x = 460
x² + 3x - 460 = 0 Product (Special Product/Quadratic Trinomial)
Solve by factoring:
(x - 20) (x+23) = 0 Factor
Solve for x:
x-20 = 0 x+23 = 0
x1 = 20 x2 = -23
Choose the positive x-value: x1 = 20
Determine their ages: Substitute 20 for x
Age of Yaya Dub: x = 20 Age of Alden: x + 3
(20) + 3 = 23
Let x age of Yaya Dub
x + 3 age of Alden
460 product of their ages
Equation:
(x) (x + 3) = 460
x² + 3x = 460
x² + 3x - 460 = 0 Product (Special Product/Quadratic Trinomial)
Solve by factoring:
(x - 20) (x+23) = 0 Factor
Solve for x:
x-20 = 0 x+23 = 0
x1 = 20 x2 = -23
Choose the positive x-value: x1 = 20
Determine their ages: Substitute 20 for x
Age of Yaya Dub: x = 20 Age of Alden: x + 3
(20) + 3 = 23
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