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Sagot :
x squared + 3x-4 =0
x squared +3x = 4
squareroot of x squared+3x = squareroot of 4
x+3x = 2
x = 2-3x
x= -1
x squared +3x = 4
squareroot of x squared+3x = squareroot of 4
x+3x = 2
x = 2-3x
x= -1
x2+3x-4=0
(x)2+3(x)=4
2x+3x=4
5x/5=4/5 :divide five on both sides and we can get.....
x=4/5
substitute x to the equation....
x2+3x-4
(4/5)2+3(4/5)-4
8/5+12/5-4
10/5-4
2-4
-2 is the answer for the equation x2+3x-4
(x)2+3(x)=4
2x+3x=4
5x/5=4/5 :divide five on both sides and we can get.....
x=4/5
substitute x to the equation....
x2+3x-4
(4/5)2+3(4/5)-4
8/5+12/5-4
10/5-4
2-4
-2 is the answer for the equation x2+3x-4
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