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calculate the wavelength of sound in air at 30 degree celsius produced by a 500-Hz loud speaker.

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The wavelength of a sound wave is given by

[tex]\boxed{\lambda = \frac{v}{f}}[/tex]

where:

λ = wavelength

v = speed of sound

f = frequency

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the speed of sound at 30°C

v = 331 + 0.6T

v = 331 + 0.6(30)

v = 349 m/s

Solving for the wavelength

[tex]\lambda = \dfrac{v}{f}[/tex]

[tex]\lambda = \dfrac{\text{349 m/s}}{\text{500 Hz}}[/tex]

[tex]\boxed{\lambda = \text{0.698 m}}[/tex]

Therefore, the wavelength of the sound wave is 0.698 m.

[tex]\\[/tex]

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