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4. The DNA present in a certain bacterial species has, on the total of nitrogenous bases, 18% of Cytosine. Calculate the% of the remaining bases present in the bacterium's DNA. A = T A + G = T + C A + G / T + C = 1 C = G​

Sagot :

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Answer:

The remaining percentage of the bases present in the DNA is equal to 82%

Percentage: it is an important mathematical tool that allows us to establish proportionalities between numbers

The x% of a quantity represents obtaining x from 100 equal parts, therefore to find x% we can divide by 100 and multiply by x, which is equivalent to making a simple and direct rule of three, in the same way if we have a quantity "a" and we want to know how much percent it represents with respect to another "b" then we make a rule of three where "b" would be 100% and we want to determine how much "a" is

So if 18% is Cytosine, then we have that the remaining% is 100%, we remove what is Cytosine, which is then:

100% - 18% = 82%

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