Answer:
solve for X
x=\frac{\sqrt{72+12y-3y^{2}}}{2}-3
x=-\frac{\sqrt{72+12y-3y^{2}}}{2}-3\text{, }y\geq 2-2\sqrt{7}\text{ and }y\leq 2\sqrt{7}+2
solve for y
y=\frac{2\sqrt{36-18x-3x^{2}}}{3}+2
y=-\frac{2\sqrt{36-18x-3x^{2}}}{3}+2\text{, }x\geq -\sqrt{21}-3\text{ and }x\leq \sqrt{21}-3
Step-by-step explanation:
4 x ^ { 2 } + 3 y ^ { 2 } + 24 x - 12 y = 36
4x^{2}+24x+3y^{2}-12y=36
4x^{2}+24x+3y^{2}-12y-36=36-36
