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Sagot :
✏️MOLALITY
[tex]\tt{\huge{\green{Solution:}}}[/tex]
The problem asks to solve for the mass of solute (theobromine). First, we need to identify the quantities to be used. These are
m = molality
mass = mass of solute
n = number of moles of solute
MW = molecular weight of solute
[tex]\text{kg}_{solv} =[/tex] kilograms of solvent
Second, we need to identify the given values. These are
m = 3.75 m
[tex]\text{kg}_{solv} =[/tex] 0.375 kg
(Note: 375 g is converted to 0.375 kg according to the definition of molality.)
Third, we need to find the number of moles of solute. The number of moles of solute is
[tex]n = m(kg_{solv})[/tex]
[tex]n = (3.75 \: m)(\text{0.375 kg})[/tex]
n = 1.40625 mol
Fourth, we need to find the molecular weight of solute. The molecular weight of solute is
MW = 7(12.01 g/mol) + 8(1.008 g/mol) + 4(14.01 g/mol) + 2(16.00 g/mol)
MW = 180.17 g/mol
Finally, we can now solve for the mass of solute Therefore, the mass of solute (theobromine) is
mass = n(MW)
mass = (1.40625 mol)(180.17 g/mol)
[tex]\boxed{\text{mass = 253 g}}[/tex]
[tex]\\[/tex]
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