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The sum of a number and 3 times its reciprocal is 19/4 . find both possible numbers

Sagot :

Answer:

The possible numbers are 4 and 3/4

Step-by-step explanation:

Let x be the number

  • x + 3(1/x) = 19/4
  • x + 3/x = 19/4
  • x²+3 / x = 19/4

cross multiplication

  • (x²+3)(4) = (19)(x)
  • 4x²+12 = 19x
  • 4x²-19x+12 = 0
  • (4x-3)(x-4) = 0

1st number

  • 4x-3 = 0
  • 4x = 3
  • x = 3/4

2nd number

  • x - 4 = 0
  • x = 4