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1.What is the percent by mass concentration of a solution that contains 6.48g of sugar dissolved dissolved in 20.8g of water?

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Sagot :

Given:

Solute: 6.48 g of sugar

Solvent: 20.8 g of H2O

Solution: 20.8 g + 6.48 g = 27.28 g

Required: % by mass concentration of the solution

Equation:

[tex]\% \: by \: mass \: = \frac{mass \: of \: solute}{mass \: of \: solution} \times 100[/tex]

Solution:

[tex]\% \: by \: mass \: = \frac{6.48 \: g}{27.28 \: g} \times 100[/tex]

[tex]\% \: by \: mass \: = 0.2375 \: \times 100 [/tex]

[tex]\% \: by \: mass \: = 23.75\%[/tex]

Therefore, the percent by mass concentration of the solution will be 23.75%

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