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Ayan na po @angelaaajoyceeee
thank you po❤ in advance❤​


Ayan Na Po Angelaaajoyceeeethank You Po In Advance class=

Sagot :

SOLVE BY SUBSTITUTION

3.) x=4 y=20

Step-by-step:

Substitute into one of the equations

[tex]x+5x=24[/tex]

Combine like terms

[tex]6x=24\\[/tex]

Divide both sides of the equation by the coefficient of variable

[tex]x=\frac{24}{6}[/tex]

Cross out the common factor

[tex]x=4[/tex]

[tex]\left \{ {{x+y=24} \atop {x=4}} \right.[/tex]

Substitute into one of the equations

[tex]4+y=24[/tex]

Rearrange unknown terms to the left side of the equation

[tex]y=24-4[/tex]

Calculate sum of the difference

[tex]y=20[/tex]

therefore the answer is: [tex]x=4 ,y=20[/tex]

4. x=12 , y=9

Solving steps:

[tex]3x-4y=0,2x+y=33[/tex]

Multiply both sides of the equation by a coefficient

[tex]3x-4y=0\\4(2x+y)=33x4[/tex]

Same solutions with number 1

SOLVE BY ELIMINATION METHOD

5.) x=1 and y=2

Let's solve your system by elimination.

  • 3x+2y=7;5x−2y=1
  • 3x+2y=7
  • 5x−2y=1

Add these equations to eliminate y:

  • 8x=8

Then solve 8x=8 for x:

  • 8x=88
  • [tex]\frac{8x}{8}=\frac{8}{8}[/tex] (Divide both sides by 8)
  • x=1

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

  • 3x+2y=7 Substitute 1 for x in 3x+2y=7:
  • (3)(1)+2y=7
  • 2y+3=7(Simplify both sides of the equation)
  • 2y+3+−3=7+−3(Add -3 to both sides)
  • 2y=4
  • [tex]\frac{2y}{2} =\frac{4}{2}[/tex]  (Divide both sides by 2)
  • y=2

6.) a=5 and b=4

Let's solve your system by elimination.

  • a+b=9;a−b=1
  • a+b=9
  • a−b=1

Add these equations to eliminate b:

  • 2a=10

Then solve2a=10for a:

  • 2a=10

[tex]\frac{2a}{2} =\frac{10}{2}[/tex] (Divide both sides by 2)

a=5

Now that we've found a let's plug it back in to solve for b.

Write down an original equation:

  • a+b=9

Substitute 5 for a in a+b=9:

  • 5 +b=9
  • b+5=9(Simplify both sides of the equation)
  • b+5+-5=9+-5 (Add -5 to both sides)
  • b=4