FORMULA:
[tex]P= 4s[/tex]
[tex]A= {s}^{2} [/tex]
SOLUTION:
First, we need to get the measurement of the side of the square. Thus,
[tex] \: \: \: A = {s}^{2} \\ 36 = {s}^{2} \\ \sqrt{36} = \sqrt{ {s}^{2} } \\ 6 = s[/tex]
We can now solve for its perimeter. That is,
[tex]P= 4s \\ \: \: \: \: \: \: \: = 4(6) \\ \: \: \: = 24[/tex]
ANSWER:
Therefore, the perimeter of Mr. Cruz's room is [tex]\huge\purple{\boxed{24 \: ft}}.[/tex]
