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the length of a rectangle is twice its width ts area s 72square centemeters find the length and width of the rectangle​

Sagot :

Mgmdelenidn

Answer:

The length is 12 cm and width is 6 cm

Step-by-step explanation:

The given are the area of the rectangle of 72[tex]cm^{2}[/tex] and the relation of its length and width.

Step 1: Identify the mathematical equation of the length and width of the given triangle. The problem states that length of the rectangle is twice its width which is equivalent to:

Length = 2 x width or L = 2w

Step 2: We know that the area of a rectangle is length multiplied by its width.

[tex]Area_{rectangle}[/tex] = L x W

Substitute the given relation of L and W, resulting to:

[tex]Area_{rectangle}[/tex] = 2w x w = 2[tex]w^{2}[/tex]

72[tex]cm^{2}[/tex]  = 2[tex]w^{2}[/tex]

Step 3: Divide both sides by 2 and take the square root of both sides.

[tex]\frac{72 cm^{2} }{2}[/tex] = [tex]\frac{2 w^{2} }{2}[/tex]  

[tex]\sqrt{36} cm^{2}[/tex] = [tex]\sqrt{w^{2} }[/tex]

w = 6 cm

Step 4: Substitute the resulting value of the rectangle's width to its relationship with the length.

L = 2w = 2 x 6 cm = 12 cm

Therefore, the length of the rectangle is 12 cm and the width is 6 cm.

To learn more about area of rectangles, click the link below:

brainly.ph/question/17152886

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