Answered

Makakuha ng maliwanag na mga sagot sa iyong mga tanong sa IDNStudy.com. Ang aming komunidad ay handang magbigay ng malalim at maaasahang mga sagot, anuman ang kahirapan ng iyong mga katanungan.

3. describe how effusion of gas does relate to the molar mass rate of effusion and time coverage?
4. what is graham's law of diffusion?
5. what are the equations used for graham's law of effusion?​

Sagot :

Mackenzie93idn

Answer:

3. The rate of effusion of a gaseous substance is inversely proportional to the square root of its molar mass. Thus the rate at which a molecule, or a mole of molecules, diffuses or effuses is directly related to the speed at which it moves.

4. Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. ... Therefore, the rates of diffusion of different gases are inversely proportional to the square roots of their mass densities.

5. From Graham's law, we can use the molar mass of each gas: rate of effusion of hydrogenrate of effusion of oxygen=√32g mol−1 √2g mol−1 =√16√1=41 rate of effusion of hydrogen rate of effusion of oxygen = 32 g mol − 1 2 g mol − 1 = 16 1 = 4 1 Hydrogen effuses four times as rapidly as oxygen.

Explanation:

#Brainlyfast

Ang iyong aktibong pakikilahok ay mahalaga sa amin. Magpatuloy sa pagtatanong at pagbahagi ng iyong nalalaman. Sama-sama tayong lumikha ng isang masiglang komunidad ng pagkatuto. Ang IDNStudy.com ay laging nandito upang tumulong sa iyo. Bumalik ka palagi para sa mga sagot sa iyong mga katanungan.