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ACTIVITY 2. View Me in Another Way and Solve! Direction: Transform each of the following equations into quadratic equation in the form ax2 + bx + c = 0 and find its solution set.
1. x(x + 3) = 28
2. (x + 1)2 + (x - 8)2 = 45
3.¹/× -×/6=2/3
4.5/4×-×+2/3=-2
Ibrainlest ko po sasagot.​


Sagot :

STANDARD FORM OF NO. 1:

[tex]x(x + 3) = 28 \\ {x}^{2} + 3x = 28 \\ x2 + 3x - 28 = 28 - 28 \\ {x}^{2} + 3x - 28 = 0[/tex]

SOLUTION SET FOR NO. 1:

[tex] {x}^{2} + 3x - 28 = 0 \\ (x + 7)(x - 4) = 0 \\ \\ x + 7 = 0 \\ x + 7 - 7 = 0 - 7 \\ x = - 7 \\ \\ x - 4 + 4 = 0 + 4 \\ x = 4[/tex]

STANDARD FORM OF NO.2:

[tex](x + 1)2 + (x - 8)2 = 45 \\( 2x + 2) + (2x - 16) = 45 \\ 4x - 14 = 45 \\ 4x - 14 - 45 = 45 - 45 \\ 4x -59 = 0[/tex]

SOLUTION SET:

[tex]4x - 59 = 0 \\ (2x - 59)(x + 1) = 0 \\ \\ \\ 2x - 59 = 0 \\ \frac{2x}{2} = \frac{59}{2} \\ x = \frac{59}{2} \: or \: 1 \frac{1}{2} [/tex]