Answered

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The sum of two numbers is 20 and the sum of their square is less than 362 . find all pairs of integers that satisfy the given conditions.

Sagot :

Jelianrosemansanadezidn

Answer:

there are two ways I know of to go about this:

1) x + y = 20

x2 + y2 < 362

x2 + (20 - x)2 < 362

x2 + 400 - 40x + x2 < 362

2x2 - 40x < -38

x2 - 20 x < -19

complete the square

(x - 10)2 < -19 + 100

(x - 10)2 < 81

x - 10 < 9

x < 19

Any of these will work:

2, 18

3, 17

4, 16

5, 15

6, 14

7, 13

8, 12

9, 11

10. 10

2) Trial and Error

1 and 19 adds to 20. The sum of their squares is exactly 362 which is too much.

All other combinations of positive integers would work.

Explanation:

#mark me as brainl

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