Jannellaayidn
Answered

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Cardo adds 5.20 moles of helium gas to a 7.25 liter floating device

that already contained 2.51 moles of helium. What is the volume of

the floating device after the addition of the extra gas? ​

Sagot :

✏️AVOGADRO'S LAW

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The problem asks to solve for the final volume of the floating device. First, we need to identify the quantities to be used. These are

V₁ = initial volume

V₂ = final volume

n₁ = initial amount of gas (in moles)

n₂ = final amount of gas (in moles)

Second, we need to identify the given values. These are

V₁ = 7.25 L

n₁ = 2.51 mol

n₂ = n₁ + 5.20 mol = 2.51 mol + 5.20 mol = 7.71 mol

[Note: 5.20 mol here is not the final amount. It is the amount added to the system. That is the reason why 5.20 moles is added to the initial amount (2.51 mol). Therefore, the final amount is 7.71 mol.]

Finally, we can now solve for the final volume. Therefore, the final volume is

[tex]V_{2} = \dfrac{V_{1}n_{2}}{n_{1}}[/tex]

[tex]V_{2} = \dfrac{(\text{7.25 L})(\text{7.71 mol})}{\text{2.51 mol}}[/tex]

[tex]\boxed{V_{2} = \text{22.3 L}}[/tex]

[tex]\\[/tex]

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