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Find five consecutive integers whose sum is 70

Sagot :

ShoukoKirishimaidn
It's 12,13,14,15, & 16 :D
Let's represent the five consecutive integers as:

1st # - x
2nd# - x+1
3rd# - x+2
4th# - x+3
5th# - x+4

To find the unknown consecutive integers and to satisfy the given problem, let's consider this equation:

x+(x+1)+(x+2)+(x+3)+(x+4)=70

Solution:

x+x+1+x+2+x+3+x+4=70
x+x+x+x+x=70-1-2-3-4
5x=70-10
5x=60
5x÷5=60÷5
*(divide both sides by 5 to extract "x")
x=12

Now that we have the value of x which is 12, we can now proceed to substitution using our representation:
x -> 12 =12
x+1 -> 12+1 =13
x+2 -> 12+2 =14
x+3 -> 12+3 =15
x+4 -> 12+4 =16
-----------------------
70=70, correct.

Hence, the answer are 12,13,14,15&16.