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If a3 = 11 and a5 = 7 and ak is the kth term of the sequence and ak = -9, then what is the value of k?
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Sagot :

Answer:

[tex] k = 13[/tex]

Step-by-step explanation:

Let a3 be the first term (a1), then a5 will be the third term (a3).

Using Arithmetic Sequence Formula

[tex] a_{k} = a_{1} + (k - 1)d[/tex]

The following values are ...

[tex] a_{1} = 11 \\ a_{3} = 5 \\ k = 3 \\ d = ?[/tex]

Subtitute the given value

[tex] a_{k} = a_{1} + (k - 1)d \\ 7 = 11 + (3 - 1)d \\ 2d = 7 - 11 \\ 2d = - 4 \: (divide \: both \: sides \: by \: 2) \\ d = - 2[/tex]

Now that we found our common difference which is -2, let a5 be the first term and ak the last term. The following values are ...

[tex] a_{1} = 7 \\ a_{k} = - 9 \\ d = - 2 \\ k = \: ?[/tex]

Using Arithmetic Sequence Formula

[tex] a_{k} = a_{1} + (k - 1)d[/tex]

Substitute the given values

[tex] - 9 = 7 + (k - 1)(-2) \\ - 2k + 2 = - 9 - 7 \\ - 2k = - 9 - 7 - 2 \\ - 2k = - 18 \: (divide \: both \: sides \: by \: - 2) \\ k = 9[/tex]

So the value of k is 9 but since we adjusted earlier, we need to adjust the value of k

[tex] k = 9 + 4 \\ (we \: subtracted \: 4 \: to \: adjust \: a_{5} \: to \: a_{1}) \\ k = 13[/tex]

So the answer is 13