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sum 7/2 and product 3​

Sagot :

Answer:

2 and 3/2

Step-by-step explanation:

a + b = 7/2

ab = 3

a = 7/2 - b  ---> substitute

(7/2 - b) b = 3

-b^2 + 7/2b = 3

b^2 - 7/2b + 3 = 0

(b - 3/2)(b - 2) = 0 ---> Apply zero property

b - 3/2 = 0, b = 3/2

b - 2 = 0, b = 2

If b = 3/2 or 2, then

b = 3/2

a + b = 7/2

a + 3/2 = 7/2

a = 7/2 - 3/2

a = 4/2

a = 2

If b = 7/2, then a = 2

b = 2

a + b = 7/2

a + 2 = 7/2

a = 7/2 - 2

a = [7 - 2(2)]/2

a = 3/2

If b = 2, then a = 3/2

Therefore, the two numbers with a sum of 7/2 and a product of 3 are 2 and 3/2.