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pasagot po para po sa summative
quadratic equation and roots
x(x-5)=0
x(x+2)=15
(x+9)²=15
(x+6)²=4
(x+5)²+(x-2)²=36​


Sagot :

Answer:

Step-by-step explanation:

1. x (x - 5) = 0

x^2 - 5x = 0

2. x (x + 2) = 15

x^2 + 2x = 15

x^2 + 2x - 15 = 15 - 15

x^2 + 2x - 15 = 0

(x - 2) (x + 3)

3. (x + 9)^2 = 15

(x + 9) (x + 9) = 15

x^2 + 9x + 9x + 81 = 15

x^2 + 18x + 81 = 15

x^2 + 18x + 81 - 15 = 15 - 15

x^2 + 18x + 66 = 0  

4. (x + 6)^2 = 4

(x + 6) (x + 6) = 4

x^2 + 6x + 6x + 36 = 4

x^2 + 12x + 36 = 4

x^2 + 12x + 36 - 4 = 4 - 4

x^2 + 12x + 32 = 0

5. (x + 5)^2 + (x - 2)^2 = 36

(x + 5) (x + 5) + (x - 2) (x - 2) = 36

x^2 + 5x + 5x + 25 + x^2 - 2x - 2x + 4 = 36

x^2 + 10x + 25 + x^2 - 4x + 4 = 36

2x^2 + 6x + 29 = 36

2x^2 + 6x + 29 - 36 = 36 - 36

2x^2 + 6x - 7 = 0