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Given:
Resistor1 (R1)= 10ohms
Resistor2 (R2)= 14ohms
Voltage (V) = 120
The circuit is in Series Connection.
Solving for the total resistance (Rt):
R1 + R2 = Rt
10ohms + 14ohms = 24ohms
Solving for the total current (It):
I = V ÷ Rt
I = 120V ÷ 24ohms
It = 5A
Therefore:
1. A. 24 Ohms
2. A. 5A