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Sagot :

Answer:

[tex]8.)2 \frac{1}{2} + \frac{3}{4} - 1 \frac{2}{5} \\ \frac{5}{2} + \frac{3}{4} - \frac{7}{5} \\ = \frac{50 + 15 - 28}{20} \\ = \frac{65 - 28}{20} \\ = \frac{37}{20} \\ = 1 \frac{17}{20} [/tex]

[tex]9.)9 \frac{3}{4} - 5 \frac{1}{2} \\ \frac{39}{4} - \frac{11}{2} \\ = \frac{39 - 22}{4} \\ = \frac{17}{4} \\ = 4 \frac{1}{4} [/tex]

1.) Zany has 1 17/20 m of ribbons left.

[tex]2 \frac{1}{2} + \frac{3}{4} \\ = \frac{5}{2} + \frac{3}{4} \\ = \frac{10}{4} + \frac{3}{4} \\ = \frac{13}{4} \\ = \frac{13}{4} - 1 \frac{2}{5} \\ = \frac{13}{4} - \frac{7}{5} \\ = \frac{65 - 28}{20} \\ = \frac{37}{20} \\ = 1 \frac{17}{20} [/tex]

2.) Paul had 4 1/4 kg of rice at the start.

[tex]9 \frac{3}{4} - 5 \frac{1}{2} \\ = \frac{39}{4} - \frac{11}{2} \\ = \frac{39}{4} - \frac{22}{4} \\ = \frac{17}{4} \: \: or \: \:4 \frac{1}{4} [/tex]