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the sum of the infinite geometric sequence 64,16,4,1
with solution please​


Sagot :

Answer:

64,16,4,1 common ratio = 1/4

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CR

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CRthus

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CRthusS∞ = 64/1-1/4

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CRthusS∞ = 64/1-1/4= 64/3/4

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CRthusS∞ = 64/1-1/4= 64/3/4= 64* 4/3

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CRthusS∞ = 64/1-1/4= 64/3/4= 64* 4/3= 85.333333...

64,16,4,1 common ratio = 1/4S∞ = a /1-r / a = first term, r = CRthusS∞ = 64/1-1/4= 64/3/4= 64* 4/3= 85.333333...= 85 1/3

Answer:

4611

pa brainliest po

thank you