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One number is 5 greater than another number.If the sum of their squares is 5 times the square of the smaller number. What are the number?

Sagot :

Answer:

10

Step-by-step explanation:

let the smaller number be n, then the 2nd will be n + 5

then :

n

2

+

(

n

+

5

)

2

=

5

n

2

so

n

2

+

n

2

+

10

n

+

25

=

5

n

2

and

3

n

2

10

n

25

=

0

To factor :

3

×

(

25

)

=

75

(require factors of (-75) that also sum to (-10) )

These are 5 and - 15 : now rewrite equation as

# 3n^2 - 15n + 5n - 25 = 0 and factoring gives

3n(n - 5 ) + 5 (n - 5 ) = 0 so (n - 5 )(3n + 5 ) = 0

n

=

5

or

n

=

5

3

but n cannot be negative and hence n = 5 and n + 5 = 10