Ysabellaangeli37idn
Answered

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A balikbayan box is pushed by a force of 225 N. The box displacement is 2.5 m. How much work is done on the box?

Sagot :

Tokamakidn

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The work done by an object exerting a force F at a distance d is given by

[tex]\boxed{W = Fd}[/tex]

where:

W = work

F = force

d = distance

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for W

W = Fd

W = (225 N)(2.5 m)

[tex]\boxed{W = \text{562.5 J}}[/tex]

Therefore, the work done on the box is 562.5 J.

[tex]\\[/tex]

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