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Sagot :
Answer : No real solutions.
Step-by-Step :
x2−6x=−15
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.x−3=±√−6
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.x−3=±√−6Step 4: Add 3 to both sides.
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.x−3=±√−6Step 4: Add 3 to both sides.x−3+3=3±√−6
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.x−3=±√−6Step 4: Add 3 to both sides.x−3+3=3±√−6x=3±√−6
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.x−3=±√−6Step 4: Add 3 to both sides.x−3+3=3±√−6x=3±√−6Answer:
x2−6x=−15Step 1: The coefficient of -6x is -6. Let b=-6.Then we need to add (b/2)^2=9 to both sides to complete the square.Add 9 to both sides.x2−6x+9=−15+9x2−6x+9=−6Step 2: Factor left side.(x−3)2=−6Step 3: Take square root.x−3=±√−6Step 4: Add 3 to both sides.x−3+3=3±√−6x=3±√−6Answer:No real solutions.
Answer:
[tex]x^{2} -6x+(6/2)^2=15+(6/2)^2\\(x-6/2)^2=24\\(x-3)^2=24\\\\solve the equation for x\\x=-2\sqrt{6} +3\\x=2\sqrt{6}+3[/tex]
Step-by-step explanation:
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