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Answer:
Approx.
0.10
m
o
l
⋅
L
−
1
Explanation:
Concentration
=
MOLES of SOLUTE
Volume of SOLUTION
So all we need to is to calculate the one quantity;
Volume of SOLUTION
has been specified to be
150
m
L
.
So,
MOLES of SOLUTE
=
0.15
⋅
m
o
l
⋅
L
−
1
×
100
×
10
−
3
L
=
?
?
mol
; this was our starting solution.
And final
CONCENTRATION
=
0.15
⋅
m
o
l
⋅
L
−
1
×
100
×
10
−
3
L
150
×
10
−
3
⋅
L
=
?
?
m
o
l
⋅
L
−
1