Leighhh7idn
Answered

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to bring us coconut his coconuts to the market, which is 15.0m from where he is, a vendor pushes his cart by a force of 10N applied at 25 with the horizontal. how much work did the vendor do?​

Sagot :

Tokamakidn

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The work done by an object exerting a force F at an angle θ and at a distance d is given by

[tex]\boxed{W = Fd \: \cos \theta}[/tex]

where:

W = work

F = force

d = distance

θ = angle of the force with the horizontal

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the work

W = Fd cos θ

W = (10 N)(15.0 m)(cos 25°)

[tex]\boxed{W = \text{135.95 J}}[/tex]

Therefore, the work done is 135.95 J.

[tex]\\[/tex]

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