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C. EXERCISE 2 DIRECTION: Follow the steps in solving the word problems by providing the following data: given, what is being asked, formula to be used, expected unit and the solution.

1: An object of mass 30 kg is placed on a hill top of height 80m. What is the potential possessed by the object? energy

2. A 10 kg mass is lifted to a height of 2 m. What is its potential energy at this position?

3. What potential energy is acquired by a hammer with a mass of 0.75 kg when raised 0.35 m?

4. A book with a mass of 1 kg is dropped from a height of 3 m. What is the potential the book when it reaches the floor? energy of​

C EXERCISE 2 DIRECTION Follow The Steps In Solving The Word Problems By Providing The Following Data Given What Is Being Asked Formula To Be Used Expected Unit class=

Sagot :

Tokamakidn

Problem 1:

Given:

m = 30 kg

g = 9.8 m/s²

h = 80 m

What is being asked:

PE

Formula to be used:

PE = mgh

Expected unit:

J

Solution:

PE = mgh

PE = (30 kg)(9.8 m/s²)(80 m)

[tex]\boxed{PE = \text{23,520 J}}[/tex]

---------------------------------------------------------

Problem 2:

Given:

m = 10 kg

g = 9.8 m/s²

h = 2 m

What is being asked:

PE

Formula to be used:

PE = mgh

Expected unit:

J

Solution:

PE = mgh

PE = (10 kg)(9.8 m/s²)(2 m)

[tex]\boxed{PE = \text{196 J}}[/tex]

---------------------------------------------------------

Problem 3:

Given:

m = 0.75 kg

g = 9.8 m/s²

h = 0.35 m

What is being asked:

PE

Formula to be used:

PE = mgh

Expected unit:

J

Solution:

PE = mgh

PE = (0.75 kg)(9.8 m/s²)(0.35 m)

[tex]\boxed{PE = \text{2.5725 J}}[/tex]

---------------------------------------------------------

Problem 4:

Given:

m = 1 kg

g = 9.8 m/s²

h = 3 m

What is being asked:

PE

Formula to be used:

PE = mgh

Expected unit:

J

Solution:

PE = mgh

PE = (1 kg)(9.8 m/s²)(3 m)

[tex]\boxed{PE = \text{29.4 J}}[/tex]

[tex]\\[/tex]

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