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find p so that p+7, 3p+9, p+3,... form an arithmetic sequence"

Sagot :

given that an arithmetic sequence as a common difference, therefore
equate the difference of the second term and the first term to the difference of the third term and the second term

such that:
(3p+9)-(p+7)=(p+3)-(3p+9)

solve for p then.