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the area of a rectangular field is 48 sq meters and its perimeter is 32 meters. Find the dimension of the field


Sagot :

Perimeter  = 2(l+w) = 32
2(l+w) = 32
l + w = 16

Area = lw = 48

We look for two numbers with a sum of 16 and a product of 48.
48 + 1 = 49 X
24 + 2 = 26 X
16 + 3 = 19 X
12 + 4 = 16 √

Therefore the dimensions of the field are 12 by 4 m.