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Find the acceleration of a car that comes to a stop from a velocity of 60m/s in a distance of 360m.​

Sagot :

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Initial Velocity (u) = 60m/s.

Final velocity (v) = 0m/s (car comes to rest)

Distance covered (s)= 360m

Now,by using 3rd equation of motion,

2as=v² - u²

2*a*360=(0)² –(60)²

720a= -3600

a= -3600/720

a= -5 m/s²

Hence, acceleration of the car is -5m/s²

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