Alynnecawarenidn
Answered

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a 12.5 kg watermelon is pushed across the floor .if the acceleration of the papaya is 4.5m/s²to the left what is the net external force exerted on the watermelon​

Sagot :

Tokamakidn

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The force acting on an object is given by

[tex]\boxed{F = ma}[/tex]

where:

F = force

m = mass

a = acceleration

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for F

F = ma

F = (12.5 kg)(4.5 m/s²)

[tex]\boxed{F = \text{56.25 N}}[/tex]

Therefore, the net external force exerted on the watermelon is 56.25 N.

[tex]\\[/tex]

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